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BASH PATCH REPORT
=================
Bash-Release: 5.2
Patch-ID: bash52-010
Bug-Reported-by: larsh@apache.org
Bug-Reference-ID:
Bug-Reference-URL: https://savannah.gnu.org/support/?110744
Bug-Description:
Bash-5.2 checks the first 128 characters of an executable file that execve()
refuses to execute to see whether it's a binary file before trying to
execute it as a shell script. This defeats some previously-supported use
cases like "self-executing" jar files or "self-uncompressing" scripts.
Patch (apply with `patch -p0'):
*** ../bash-5.2-patched/general.c 2022-11-07 10:31:42.000000000 -0500
--- general.c 2022-11-18 14:48:45.000000000 -0500
***************
*** 684,687 ****
--- 684,688 ----
{
register int i;
+ int nline;
unsigned char c;
***************
*** 690,702 ****
/* Generally we check the first line for NULs. If the first line looks like
! a `#!' interpreter specifier, we just look for NULs anywhere in the
! buffer. */
! if (sample[0] == '#' && sample[1] == '!')
! return (memchr (sample, '\0', sample_len) != NULL);
for (i = 0; i < sample_len; i++)
{
c = sample[i];
! if (c == '\n')
return (0);
if (c == '\0')
--- 691,701 ----
/* Generally we check the first line for NULs. If the first line looks like
! a `#!' interpreter specifier, we look for NULs in the first two lines. */
! nline = (sample[0] == '#' && sample[1] == '!') ? 2 : 1;
for (i = 0; i < sample_len; i++)
{
c = sample[i];
! if (c == '\n' && --nline == 0)
return (0);
if (c == '\0')
*** ../bash-5.2/patchlevel.h 2020-06-22 14:51:03.000000000 -0400
--- patchlevel.h 2020-10-01 11:01:28.000000000 -0400
***************
*** 26,30 ****
looks for to find the patch level (for the sccs version string). */
! #define PATCHLEVEL 9
#endif /* _PATCHLEVEL_H_ */
--- 26,30 ----
looks for to find the patch level (for the sccs version string). */
! #define PATCHLEVEL 10
#endif /* _PATCHLEVEL_H_ */
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